The awards and notoriety just keep coming for Raiders’ defensive end Maxx Crosby. After his dominant performance on Sunday against the Bengals, the 2019 fourth-round pick from Eastern Michigan was named the AFC Defensive Player of the Week for his game in Week 11.
Crosby finished the contest with five tackles, four sacks and three tackles for a loss. He recorded three sacks in the fourth quarter as the Bengals were trying to find a way to tie the ballgame. However, Crosby was in the backfield all day long.
Crosby should have a chance to have another big game this week as the Raiders will travel to New York to take on the Jets. With the Jets’ subpar offensive line, look for Crosby to continue his hot streak into Week 12.
