The Jamal Adams contract saga is finally over.
According to a report by Ian Rapoport at NFL Network, the Seahawks and their star strong safety have come to an agreement on a new four-year, $70 million deal. The contract includes $38 million in guarantees.
The #Seahawks have agreed to terms on a large extension for star S Jamal Adams, a 4-year, $70M deal that makes him the league’s highest paid safety, I’m told. He gets $38M guaranteed, breaking the stalemate. A long time coming and well-deserved. 💰💰💰
— Ian Rapoport (@RapSheet) August 17, 2021
Adams had been staging a “hold-in” at training camp – by showing up but not practicing – in the hopes of getting $40 million in guarantees, but Seattle’s front office had apparently dug in and made their final offer. With the threat of franchise tags in 2022 and 2023 hanging over him, Adams ultimately did not have enough leverage.
The new deal makes Adams the highest-paid safety in the NFL by a comfortable margin. The previous champ was Justin Simmons of the Broncos, whose deal averaged $15,250,000 a year.
