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USA Today Sports Media Group
USA Today Sports Media Group
Sport
Matthew Stevens

Lamar Jackson wins his 4th AFC Offensive Player of the Week award of 2019

At this point, the NFL might as well start engraving Baltimore Ravens quarterback Lamar Jackson’s name on the MVP trophy. For the fourth week this season, Jackson was named the AFC’s Offensive Player of the Week. This time for his performance in a Week 12 against the Los Angeles Rams.

Going up against the Rams’ talented defense, Jackson once again picked apart a team en route to a lopsided, 45-6, victory. He completed 15-of-20 passes for 169 yards, five touchdown throws, no interceptions and a 139.4 passer rating. In addition, he added 95 rushing yards on eight carries including yet another insane run. And he did all this while playing little more than three quarters before getting pulled in favor of backup Robert Griffin III with the game already out of control.

It was a November to remember for Jackson, winning the award in three of the four weeks of the month. The only game he didn’t win — Week 11 against the Houston Texans — Jackson very well could have after throwing four touchdown passes and running for 79 yards during Baltimore’s 41-7 victory.

Jackson becomes just the 11th NFL player to win the Player of the Week honor at least four times in a single season. The last time it was done was 2015 when Carolina Panthers quarterback Cam Newton won it five times before winning the MVP award that season.

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