Denver Broncos safety Kareem Jackson has been named the AFC Defensive Player of the Week, the NFL announced Wednesday. Jackson had a standout performance in Denver’s 38-24 win over the Houston Texans on Sunday.
Facing the team he spent the first nine years of his career with, Jackson totaled 11 tackles, one interception and three pass breakouts. He also returned a fumble 70 yards for a touchdown. He became the first defender with at least 10 tackles, a fumble returned for a score and an interception in the same game since former Chicago Bears linebacker Brian Urlacher in 2011.
On the year, Jackson has totaled 69 tackles, eight pass breakups, two interceptions and one forced fumble. His 11 tackles on Sunday tied a career high.
This marks the first time a Broncos defender has taken home a conference award since outside linebacker Von Miller won in Week 11 last season. Jackson is the 34th Denver defender to take home the award since 1984.
